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53 lines
1.2 KiB
53 lines
1.2 KiB
2 years ago
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Assign elements to processors evenly #elem/#proc --
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std::vector<std::vector<int>> node_to_proc(#node)
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blk = 1
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st_blk = 0
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en_blk = st_blk + #blk-elem
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for each (proc) {
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node_on_proc(#node) = false
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ste = start element
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ene = end element
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end = min(ene, en_blk)
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for each element(ste..ene) {
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foreach node in element {
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if (!node_on_proc(node)) {
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node_to_proc(node).push_back(proc);
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node_on_proc(node) = true;
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}
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}
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}
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if (end < ene) get next block
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else, continue with same block
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}
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... All interior nodes will have node_to_proc(node).size() == 1
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... All unconnected nodes will have node_to_proc(node).size() == 0
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... Add the granularity of element blocks
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Each block has beg, end range, and connectivity size.
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... Better to iterate by block:
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foreach (element block)
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-- get connectivity
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find st_proc
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find end_proc
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proc for an element (0-based):
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proc = elem / elem-per-proc +
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elem-per-proc = #elem / #proc
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extra = #elem % #proc
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elementCount = elem_per_proc + (proc < extra ? 1 : 0);
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if (proc < extra) {
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startElement = (el_per_proc+1) * (proc);
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} else {
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startElement = (el_per_proc) * (proc) + remain;
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}
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