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60 lines
2.0 KiB
60 lines
2.0 KiB
2 years ago
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C Copyright(C) 1999-2020 National Technology & Engineering Solutions
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C of Sandia, LLC (NTESS). Under the terms of Contract DE-NA0003525 with
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C NTESS, the U.S. Government retains certain rights in this software.
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C
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C See packages/seacas/LICENSE for details
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C=======================================================================
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SUBROUTINE CNTLK3 (NELBLK, LENE, NLNKE, LENLNK, NFACES, NAMELB,
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$ NLNKSC)
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C=======================================================================
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C --*** CNTLK3 *** (MESH) Return link array length and number faces (3D)
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C -- Written by Amy Gilkey - revised 03/04/88
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C --
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C --CNTLK3 returns the maximum length of the connectivity array for
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C --the faces and the maximum number of faces that may be defined.
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C --
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C --Parameters:
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C -- NELBLK - IN - the number of element blocks
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C -- LENE - IN - the cumulative element counts by element block
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C -- NLNKE - IN - the number of nodes per element
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C -- LENLNK - OUT - the length of the connectivity array
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C -- NELEMS - OUT - the number of elements
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INTEGER LENE(0:*)
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INTEGER NLNKE(*)
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CHARACTER*(*) NAMELB(*)
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INTEGER NLNKSC(*)
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NFACES = 0
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LENLNK = 0
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DO 100 IELB = 1, NELBLK
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NUME = LENE(IELB) - LENE(IELB-1)
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IF (NAMELB(IELB)(:3) .EQ. 'HEX' .and. NLNKE(IELB) .GE. 8) THEN
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NF = 6
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NL = 4
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ELSE IF (NAMELB(IELB)(:3) .EQ. 'TET') THEN
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NF = 4
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C ... Even though there are only 3 nodes per face, we fake that there
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C are 4 nodes for consistency with the rest of blot...
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NL = 4
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ELSE IF (NAMELB(IELB)(:3) .EQ. 'WED') THEN
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NF = 5
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NL = 4
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ELSE IF (NAMELB(IELB)(:3) .EQ. 'PYR') THEN
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NF = 5
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NL = 4
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ELSE
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NF = 1
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NL = NLNKE(IELB)
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END IF
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NLNKSC(IELB) = NL
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NFACES = NFACES + NUME * NF
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LENLNK = LENLNK + NUME * NF * NL
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100 CONTINUE
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RETURN
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END
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